## University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson

# Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 52

#### Answer

$0.73$ rad

#### Work Step by Step

The formula to calculate the angle between two planes is: $\theta = \cos ^{-1} (\dfrac{p \cdot q}{|p||q|})$ Here, $p=\lt 0,4,3 \gt$ and $q=\lt 3,2,6 \gt$ $|p|=\sqrt{0^2+4^2+3^2}= 5$ and $|q|=\sqrt{3^2+2^2+6^2}= 7$ Thus, $\theta = \cos ^{-1} (\dfrac{p \cdot q}{|p||q|})=\cos ^{-1} (\dfrac{26}{ 35})$ or, $\theta = 0.73$

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