University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 33

Answer

$2 \sqrt {30}$

Work Step by Step

The formula to calculate the distance for two vectors is given by: $d=\dfrac{|u \times v|}{|v|}$ Thus, we have $u \times v=\lt -24,-48,0 \gt $ and $|u \times v|=\sqrt{(-24)^2+(-48)^2+(0)^2}=24 \sqrt 5$ Now, $d=\dfrac{|u \times v|}{|v|}=\dfrac{24 \sqrt 5}{2 \sqrt 6}=2 \sqrt {30}$
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