Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 8: Techniques of Integration - Section 8.3 - Trigonometric Integrals - Exercises 8.3 - Page 462: 1


\begin{aligned} \int \cos 2 x d x =\frac{1}{2} \sin 2 x+C \end{aligned}

Work Step by Step

Given $$\int \cos 2 x d x $$ So, we have \begin{aligned} I&=\int \cos 2 x d x\\ &=\frac{1}{2} \int \cos 2 x \cdot 2 d x\\ &=\frac{1}{2} \sin 2 x+C \end{aligned}
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