Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.3 - Exponential Functions - Exercises 7.3 - Page 391: 77

Answer

$$ y ^{\prime}=\frac{1}{\ln 10}$$

Work Step by Step

Given $$ y =\log _{10} e^x $$ Since $$\log_{a}z=\frac{\ln z}{\ln a}$$ So, we have \begin{aligned} y& =\log _{10} e^x\\ &=\frac{\ln e^x}{\ln 10}\\ &=\frac{x\ln e}{\ln 10} \\ &=\frac{x }{\ln 10}\\ &\Rightarrow y^{\prime}=\frac{1}{\ln 10} \end{aligned}
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