Answer
$$\frac{{dy}}{{dx}} = {2^x}\left( {\ln 2} \right)$$
Work Step by Step
$$\eqalign{
& y = {2^x} \cr
& {\text{Find the derivative of }}y{\text{ with respect to }}x \cr
& \frac{{dy}}{{dx}} = \frac{d}{{dx}}\left[ {{2^x}} \right] \cr
& {\text{use the rule }}\frac{d}{{dx}}\left[ {{a^x}} \right] = {a^x}\left( {\ln a} \right);
{\text{}}{\text{let }}a = 2 \cr
& \frac{{dy}}{{dx}} = {2^x}\left( {\ln 2} \right) \cr} $$
