Answer
-2
Work Step by Step
av(f)=$(\frac{1}{1-0})\int^{1}_{0}(-3x^2-1)dx$
=$-3\int^{1}_{0}x^2dx-\int^{1}_{0}1dx$
=$-3(\frac{1^3}{3}-(1-0))=-2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 276: 57
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