Answer
0
Work Step by Step
$\int^{2}_{0}(3x^2+x-5)$dx
=3$\int^{2}_{0}x^2dx+\int^{2}_{0}xdx-\int^{2}_{0}5dx$
=3$[\frac{2^3}{3}-\frac{0^3}{3}]+[\frac{2^2}{2}-\frac{0^2}{2}]$
=5[2-0]=(8+2)-10
=0
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 49
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