Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 25


$b^2 - a^2$

Work Step by Step

$\int ^b_a 2sds$ =$\frac{1}{2}$ b(2b)-$\frac{1}{2}a(2a) =b^2 - a^2$
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