Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 36

Answer

$\frac{\pi^3}{24}$

Work Step by Step

$\int^{\frac{\pi}{2}}_{0} O^2$ =$\frac{\frac{(\pi}{2})}{3}$ =$\frac{\pi^3}{24}$
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