## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 17

#### Answer

$\frac{9}{2}\pi$ square Units

#### Work Step by Step

The area of Semicircle is A=$\frac{1}{2}\pi r^2$ =$\frac{1}{2}\pi(3)^2$ =$\frac{9}{2}\pi$ =$\int^3_{-3}\sqrt{9-x^2}dx$ =$\frac{9}{2}\pi$ square Units

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