## Thomas' Calculus 13th Edition

$\frac{9}{2}\pi$ square Units
The area of Semicircle is A=$\frac{1}{2}\pi r^2$ =$\frac{1}{2}\pi(3)^2$ =$\frac{9}{2}\pi$ =$\int^3_{-3}\sqrt{9-x^2}dx$ =$\frac{9}{2}\pi$ square Units