Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 275: 17

Answer

$\frac{9}{2}\pi $ square Units

Work Step by Step

The area of Semicircle is A=$\frac{1}{2}\pi r^2$ =$\frac{1}{2}\pi(3)^2$ =$\frac{9}{2}\pi$ =$\int^3_{-3}\sqrt{9-x^2}dx$ =$\frac{9}{2}\pi $ square Units
Small 1554787037
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.