Answer
a) $-\dfrac{1}{x^{2}}+C$
b) $\dfrac{-1}{4x^{2}}+C$
c) $\dfrac{x^4}{4}+\dfrac{1}{2x^{2}}+C$
Work Step by Step
a) The anti-derivative is:
Thus, $(-2)(\dfrac{x^{-3+1}}{-3+1})+C=\dfrac{1}{x^{2}}+C$
b) The anti-derivative is:
Thus, $(\dfrac{1}{2}\dfrac{x^{-3+1}}{-3+1})+C=(\dfrac{-1}{4x^{2}})+C$
c) The anti-derivative is:
Thus, $(\dfrac{x^4}{4})-(\dfrac{x^{-3+1}}{-3+1})+C=\dfrac{x^4}{4}+(\dfrac{1}{2x^{2}})+C$
