Answer
a) $-\dfrac{1}{x}+C$
b) $-\dfrac{5}{x}+C$
c) $2x+\dfrac{5}{x}+C$
Work Step by Step
a) The anti-derivative is:
Thus, $(\dfrac{x^{-2+1}}{-2+1})+C=-\dfrac{1}{x}+C$
b) The anti-derivative is:
Thus, $5(-\dfrac{1}{x}+C)=(-\dfrac{5}{x})+C$
c) The anti-derivative is:
Thus, $[2x-(\dfrac{-5}{x}+C)]=2x+(\dfrac{5}{x})+C$