## Thomas' Calculus 13th Edition

$\dfrac{-4}{x^{1/4}}+C$
As we know $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$ Thus, $\int x^{-5/4}dx=(\dfrac{x^{-5/4+1}}{-5/4+1})+C=\dfrac{-4}{x^{1/4}}+C$