Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 238: 3

Answer

a) $x^{-3}+C$ b) $\dfrac{-x^{-3}}{3}+C$ c) $\dfrac{-x^{-3}}{3}+x^2+3x+C$

Work Step by Step

a) The anti-derivative is: Thus, $(\dfrac{-3}{-4+1})x^{-4+1}+C=x^{-3}+C$ b) The anti-derivative is: Thus, $(\dfrac{1}{-4+1})x^{-4+1}+C=\dfrac{-x^{-3}}{3}+C$ c) The anti-derivative is: Thus, $(\dfrac{1}{-4+1})x^{-4+1}+(\dfrac{2}{1+1})x^{1+1}+3x+C=\dfrac{-x^{-3}}{3}+x^2+3x+C$
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