Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 175: 51

Answer

$37.87$

Work Step by Step

Step 1. On the Moon, $W=a+\frac{b}{g_m}$, $dW_m=-\frac{b}{g_m^2}dg=-\frac{b}{5.2^2}dg$ Step 2. On the Earth, $W=a+\frac{b}{g_e}$, $dW_e=-\frac{b}{g_e^2}dg=-\frac{b}{32^2}dg$ Step 3. The ratio: $\frac{dW_m}{dW_e}=\frac{-\frac{b}{5.2^2}dg}{-\frac{b}{32^2}dg}=(\frac{32}{5.2})^2\approx37.87$. It seems that the work change is more sensitive to the gravity change on the Moon than on the Earth.
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