Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 175: 47

Answer

$\frac{1}{3}\%$

Work Step by Step

Step 1. Given $V=\pi h^3$, we have $dV=3\pi h^2dh$ Step 2. Percentage: $\frac{dV}{V}=\frac{3\pi h^2dh}{\pi h^3}=\frac{3dh}{ h}$ Step 3. Since $\frac{dV}{V}=1\%$, we have $\frac{3dh}{ h}=1\%$ and $\frac{dh}{ h}=\frac{1}{3}\%$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.