Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 175: 28

Answer

$\frac{1}{\sqrt {x^3}}csc^2(\frac{1}{\sqrt x})dx$

Work Step by Step

Given $y=2cot(\frac{1}{\sqrt x})$, we have $dy=-2csc^2(\frac{1}{\sqrt x})(-\frac{1}{2\sqrt {x^3}})dx=csc^2(\frac{1}{\sqrt x})(\frac{1}{\sqrt {x^3}})dx=\frac{1}{\sqrt {x^3}}csc^2(\frac{1}{\sqrt x})dx$
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