Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.6 - Limits Involving Infinity; Asymptotes of Graphs - Exercises 2.6 - Page 99: 108

Answer

See graph and explanations.

Work Step by Step

See graph; when $x\to-\infty, y\to0$ or $\lim_{x\to -\infty}sin(\frac{\pi}{x^2+1})=0$; while when $x\to\infty, y\to0$ or $\lim_{x\to \infty}sin(\frac{\pi}{x^2+1})=0$; the asymptote of the function is $y=0$
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