Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.6 - Limits Involving Infinity; Asymptotes of Graphs - Exercises 2.6 - Page 99: 101

Answer

See graph and explanations.

Work Step by Step

See graph; when $x\to1^+, y\to-\infty$ or $\lim_{x\to 1^+}\frac{x^2-4}{x-1}=-\infty$; while when $x\to1^-, y\to\infty$ or $\lim_{x\to 1^-}\frac{x^2}{x-1}=\infty$, the asymptote of the function is $x=1$
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