Answer
See graph and explanations.
Work Step by Step
See graph; when $x\to1^+, y\to-\infty$ or $\lim_{x\to 1^+}\frac{x^2-4}{x-1}=-\infty$;
while when $x\to1^-, y\to\infty$ or $\lim_{x\to 1^-}\frac{x^2}{x-1}=\infty$,
the asymptote of the function is $x=1$