Answer
See graph and explanations.
Work Step by Step
See graph; when $x\to0^+, y\to-\infty$ or $\lim_{x\to 0^+}\frac{x^2-1}{x}=-\infty$;
while when $x\to0^-, y\to\infty$ or $\lim_{x\to 0^-}\frac{x^2-1}{x}=\infty$;
the asymptote of the function is $x=0$