Answer
See graph and explanations.
Work Step by Step
See graph, when $x\to-2^+, y\to-\infty$ or $\lim_{x\to -2^+}\frac{x}{\sqrt {4-x^2}}=-\infty$;
while when $x\to2^-, y\to\infty$ or $\lim_{x\to 2^-}\frac{x}{\sqrt {4-x^2}}=\infty$;
the asymptotes of the function are $x=-2$, and $x=2$
