Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.6 - Limits Involving Infinity; Asymptotes of Graphs - Exercises 2.6 - Page 98: 77

Answer

Yes, we can conclude that $\displaystyle \lim_{x\rightarrow-\infty}\frac{f(x)}{g(x)}=2.$

Work Step by Step

If $\displaystyle \lim_{x\rightarrow\infty}\frac{f(x)}{g(x)}=2$, then we know that: 1. f and g have the same degree (say, n) and, after dividing both the numerator and denominator with $x^{n}$, we find that: 2. the leading coefficient of f is 2$\times$(leading coefficient of g) If we want $\displaystyle \lim_{x\rightarrow-\infty}\frac{f(x)}{g(x)}$ we would also divide both the numerator and denominator with $x^{n} ,$ and the result will also be the ratio of the leading coefficients, 2.
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