Answer
$+\infty$
Work Step by Step
When $x\rightarrow 0$, from either the positive ($x\rightarrow 0^{+})$ or the negative ($x\rightarrow 0^{-}$) side, the numerator is positive.
In the denominator, $x^{2/3}= (x^{1/3})^{2}$, which is positive, approaching zero.
Thus, the whole fraction $\displaystyle \frac{1}{x^{2/3}}\rightarrow+\infty \qquad$ ... ( $\displaystyle \frac{pos.}{neg.}$ )
