Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Additional and Advanced Exercises - Page 104: 31


$$ y=2 x .$$

Work Step by Step

Since the highest power of $ x $ in the numerator is 1 more than the highest power of $ x $ in the denominator, there is an oblique asymptote. $$ y=\frac{2 x^{3 / 2}+2 x-3}{\sqrt{x}+1}=2 x-\frac{3}{\sqrt{x}+1},$$ Thus the oblique asymptote is $$ y=2 x $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.