Answer
$$4$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 2} \frac{\sin \left(x^{2}-4\right)}{x-2}&=\lim _{x \rightarrow 2} \frac{\sin \left(x^{2}-4\right)}{x^{2}-4} \cdot(x+2)\\
&=\lim _{x \rightarrow 2} \frac{\sin \left(x^{2}-4\right)}{x^{2}-4} \cdot \lim _{x \rightarrow 2}(x+2)\\
&=1 \cdot 4\\
&=4
\end{align*}