Answer
$$1$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 0} \frac{\sin \left(x^{2}+x\right)}{x}&=\lim _{x \rightarrow 0} \frac{\sin \left(x^{2}+x\right)}{x^{2}+x} \cdot(x+1)\\
&=\lim _{x \rightarrow 0} \frac{\sin \left(x^{2}+x\right)}{x^{2}+x} \cdot \lim _{x \rightarrow 0}(x+1)\\
&=1 \cdot 1\\
&=1
\end{align*}