Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Additional and Advanced Exercises - Page 104: 26

Answer

$$0$$

Work Step by Step

\begin{align*} \lim _{x \rightarrow 0^{+}} \frac{\sin x}{\sin \sqrt{x}}&=\lim _{x \rightarrow 0^{+}} \frac{\sin x}{x} \cdot \frac{\sqrt{x}}{\sin \sqrt{x}} \cdot \frac{x}{\sqrt{x}}\\ &=1 \cdot \lim _{x \rightarrow 0^{+}} \frac{1}{\left(\frac{\sin \sqrt{x}}{\sqrt{x}}\right)} \cdot \lim _{x \rightarrow 0^{+}} \sqrt{x}\\ &=1 \cdot 1 \cdot 0\\ &=0 \end{align*}
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