Answer
$$0$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 0^{+}} \frac{\sin x}{\sin \sqrt{x}}&=\lim _{x \rightarrow 0^{+}} \frac{\sin x}{x} \cdot \frac{\sqrt{x}}{\sin \sqrt{x}} \cdot \frac{x}{\sqrt{x}}\\
&=1 \cdot \lim _{x \rightarrow 0^{+}} \frac{1}{\left(\frac{\sin \sqrt{x}}{\sqrt{x}}\right)} \cdot \lim _{x \rightarrow 0^{+}} \sqrt{x}\\
&=1 \cdot 1 \cdot 0\\
&=0
\end{align*}