Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.2 - Double Integrals over General Regions - Exercises 15.2 - Page 882: 29



Work Step by Step

Consider $\iint_{R} f(u,v) dA= \int_{-2}^{0} \int_v^{-v} 2 dp dv= \int_{-2}^{0} [2p]_{v}^{-v} dv$ or, $= \int_{-2}^{0} -2v-2v dv$ or, $= [-2v^2]_{-2}^{0}$ Thus, we have $I=2\times (-2)^2 =8$
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