Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.2 - Double Integrals over General Regions - Exercises 15.2 - Page 882: 22



Work Step by Step

Consider: $I= \int_{1}^{2} \int_{y}^{y^2} dx dy$ or, $= \int_1^{2} [x]_{y}^{y^2} dy $ or, $= \int_1^{2} [y^2-y] dy $ or, $=[\dfrac{y^3}{3}-\dfrac{y^2}{2}]_1^2$ So, $I=\dfrac{8}{3} -2-\dfrac{1}{3}+\dfrac{1}{2}=\dfrac{5}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.