Answer
Limit does not exist
Work Step by Step
Consider our approach : $(x,y) \to (0,0)$ along $y=kx^2; m\ne 1$
Then, we get $\lim\limits_{x \to 0}\dfrac{x^2+kx^2}{mx^2}=\dfrac{1+k}{k}$
This shows that there are multiple limit values when the approach is different, so, the limit does not exist at the point (0,0) for the function $f(x,y)=\dfrac{x^2+y}{y}$ .
