Answer
Limit does not exist
Work Step by Step
Consider a approach : $(x,y) \to (0,0)$ along $y=kx^2$
Then, we get $\lim\limits_{x \to 0}\dfrac{x^4-(kx)^2}{x^4+(kx)^2}=\lim\limits_{x \to 0}\dfrac{1-k^2}{1+k^2}$
or, $\lim\limits_{x \to 0}\dfrac{1-k^2}{1+k^2}=\dfrac{1-k^2}{1+k^2}$
This shows that there are multiple limit values, thus, the limit does not exist at the point (0,0) for the function $f(x,y)=\dfrac{x^4-y^2}{x^4+y^2}$.
