#### Answer

limit does not exist

#### Work Step by Step

Consider first approach : $(x,y) \to (0,0)$ along $y=0$
This implies that $\lim\limits_{x \to 0}\dfrac{x^4}{x^4+(0)^2}=1$
Next, let us consider our second approach : $(x,y) \to (0,0)$ along $y=x^2$
This implies that $\lim\limits_{x \to 0}\dfrac{x^4}{x^4+(x^2)^2}=\dfrac{1}{2}$
This shows that there are different limit values for different approach, so, the limit does not exist at the point (0,0) for the function $f(x,y)=\dfrac{x^4}{x^4+y^2}$.