Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.2 - Limits and Continuity in Higher Dimensions - Exercises 14.2 - Page 796: 7

Answer

1/2

Work Step by Step

The point (0,ln2) is in the equation's domain, so plug the point into the equation to evaluate the limit: $e^{0-ln2}=e^{-ln2}=1/2$
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