Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Practice Exercises - Page 865: 36



Work Step by Step

$2xy+e^{x+y}-2=0$ $2ydx+2xdy+e^{x+y}dx+e^{x+y}dy=0$ $2\ln2dx+e^{\ln2}dx+e^{\ln2}dy=0$ when $x=0,y=\ln2$ $2\ln2dx+2dx+2dy=0$ $2dy=-(2\ln2+2)dx$ $\frac{dy}{dx}=-(\ln2+1)$
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