Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Practice Exercises - Page 865: 35



Work Step by Step

$1-x-y^{2}-sin(xy)=0$ $-dx-2ydy-cos(xy)ydx-cos(xy)xdy=0$ $-dx-2dy-dx=0$ when $x=0,y=1$ $2dy=-2dx$ $\frac{dy}{dx}=-1$
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