Answer
-1
Work Step by Step
$1-x-y^{2}-sin(xy)=0$
$-dx-2ydy-cos(xy)ydx-cos(xy)xdy=0$
$-dx-2dy-dx=0$ when $x=0,y=1$
$2dy=-2dx$
$\frac{dy}{dx}=-1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Practice Exercises - Page 865: 35
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