Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 25


$f_{xx}=0$ $f_{yy}=\frac{2x}{y^3}$ $ f_{xy}=f_{yx}=-\frac{1}{y^2}$

Work Step by Step

$f(x,y)=y+\frac{x}{y}$ $f_{x}=\frac{1}{y}, f_{xx}=0, f_{yx}=-\frac{1}{y^2}$ $f_{y}=1-\frac{x}{y^2}, f_{yy}=\frac{2x}{y^3}, f_{xy}= f_{yx}$
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