Answer
$g_{xx}=e^{x}-y\times Sin(x)$
$g_{yy}=0$
$g_{xy}=g_{yx}=Cos(x)$
Work Step by Step
$g(x,y)=e^{x}+y\times Sin(x)$
$g_{x}=e^{x}+y\times Cos(x)$
$g_{xx}=e^{x}-y\times Sin(x)$
$g_{yx}=Cos(x)$
$g_{y}=Sin(x)$
$g_{yy}=0$
$g_{xy}=g_{yx}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 26
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