Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 14

Answer

$-(\dfrac{\pi}{4})$

Work Step by Step

Consider $l=\lim\limits_{(x,y,z) \to (1,-1,-1)} \tan^{-1} (x+y+z)$ and $l=\tan^{-1} (1-1-1)=\tan^{-1} (-1)$ Hence, $l=-\tan^{-1} (\tan (\dfrac{\pi}{4}))=-(\dfrac{\pi}{4})$
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