# Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 13

$1$

#### Work Step by Step

Consider $l=\lim\limits_{(x,y,z) \to (1,-1,e)} \ln |x+y+z|$ and $l=\ln |1+(-1)+e|$ Hence, $l=|=\ln |1-1+e|=\ln e=1$

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