## Thomas' Calculus 13th Edition

$\langle 800\cos 115^{o},\ 800\sin 115^{o}\rangle \approx\langle-338.1,\ 725.0\rangle$
The angle "$25^{\circ}$ west of north", relative to east, the +x axis, is: $90^{o}+25^{o}=115^{o}.$ (second quadrant) Velocity is a vector ${\bf v}$ with components $= \langle v_{1},\ v_{2}\rangle$ $v_{1}$ = the x-component = $800\cos 115^{o},$ $v_{2}$ = the y-component = $800\sin 115^{o}$ $\langle 800\cos 115^{o},\ 800\sin 115^{o}\rangle \approx\langle-338.1,\ 725.0\rangle$