Answer
$\langle 800\cos 115^{o},\ 800\sin 115^{o}\rangle \approx\langle-338.1,\ 725.0\rangle$
Work Step by Step
The angle "$25^{\circ}$ west of north", relative to east, the +x axis, is:
$90^{o}+25^{o}=115^{o}.$
(second quadrant)
Velocity is a vector ${\bf v} $ with components $= \langle v_{1},\ v_{2}\rangle$
$v_{1}$ = the x-component = $800\cos 115^{o},$
$v_{2}$ = the y-component = $800\sin 115^{o}$
$\langle 800\cos 115^{o},\ 800\sin 115^{o}\rangle \approx\langle-338.1,\ 725.0\rangle$
