Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 705: 40



Work Step by Step

Since, we are given that $\overrightarrow{AB}=-7i+3j+8k$,$A=(-2,-3,6)$ and let us suppose that $B=(p,q,r)$ $\overrightarrow{AB}=(p+2)i+(q+3)j+(r-6)k$ or, $(p+2)i+(q+3)j+(r-6)k=-7i+3j+8k$ Equate the terms $p+2=-7, q+3=3, r-6=8$ so, $p=-9,q=0,r=14$ Hence, our point is: $B=(-9,0,14)$
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