## Thomas' Calculus 13th Edition

$(-9,0,14)$
Since, we are given that $\overrightarrow{AB}=-7i+3j+8k$,$A=(-2,-3,6)$ and let us suppose that $B=(p,q,r)$ $\overrightarrow{AB}=(p+2)i+(q+3)j+(r-6)k$ or, $(p+2)i+(q+3)j+(r-6)k=-7i+3j+8k$ Equate the terms $p+2=-7, q+3=3, r-6=8$ so, $p=-9,q=0,r=14$ Hence, our point is: $B=(-9,0,14)$