## Thomas' Calculus 13th Edition

$(4,-3,5)$
Since, we are given that $\overrightarrow{AB}=i+4j-2k$ Now, let us suppose $A=(p,q,r)$ This implies that $\overrightarrow{AB}=(5-p)i+(1-q)j+(3-r)k$ or, $(5-p)i+(1-q)j+(3-r)k=i+4j-2k$ Equate the terms. $5-p=1, 1-q=4, 3-r=-2$ So, $p=4,q=-3,r=5$ Hence, we have out point: $A=(4,-3,5)$