Thomas' Calculus 13th Edition

Published by Pearson

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 705: 31

Answer

(a) $2i$ (b) $-\sqrt 3k$ (c) $\dfrac{3}{10}j+\dfrac{2}{5}k$ (d) $6j-2j+3k$

Work Step by Step

Need to find parts a,b,c,d as follows: (a) $2(i)=2i$ (b) $\sqrt 3(-k)=-\sqrt 3k$ (c) $\dfrac{1}{2}(\dfrac{3}{5}j+\dfrac{4}{5}k)=(\dfrac{3}{10}j+\dfrac{4}{10}k)=\dfrac{3}{10}j+\dfrac{2}{5}k$ (d) $7(\dfrac{6}{7}i-\dfrac{2}{7}j+\dfrac{3}{7}k)=6j-2j+3k$

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