Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.2 - Infinite Series - Exercises 10.2 - Page 579: 30

Answer

Test is Inconclusive.

Work Step by Step

Given: $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}$ Since, the given series $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}$ has degree of denominator is less than numerator. Thus, we have $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}=0$ Hence, The Test is Inconclusive.
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