Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.2 - Infinite Series - Exercises 10.2 - Page 579: 21

Answer

$\dfrac{7}{9}$

Work Step by Step

Here, $0.7777= \dfrac{7}{10}+\dfrac{7}{(10)^2}+\dfrac{7}{(10)^3}+....=\dfrac{7}{10}(1+ \dfrac{1}{10}+ \dfrac{1}{(10)^2}+..)$ Formula to find the sum of a geometric series $1+ \dfrac{1}{10}+ \dfrac{1}{(10)^2}+..$ is $S=\dfrac{a}{1-r}$ Now, $a=1, r=\dfrac{1}{10}=0.01$; Then,we have $S=\dfrac{7}{10}(\dfrac{1}{1-0.01})=\dfrac{7}{9}$
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