Answer
$A(t)=\displaystyle \frac{6.3}{1+4.8(1.2)^{-t}}$
Limiting value (level-off value) is $N=6.3$
Work Step by Step
(We use desmos.com for the calculations/graph below.)
Logistic Model form: $\displaystyle \quad R=\frac{N}{1+Ab^{-t}}$
1. create a table with variable names $t$ and $R$ (R for research articles) and enter the data.
2. in the next free cell, enter
$R\sim N/1+Ab^{-t}$
The calculator returns $\left\{\begin{array}{l}
N=6.3\\
A=4.8\\
b=1.2
\end{array}\right.$
(rounded to 2 significant figures.)
$R=A(t)=\displaystyle \frac{6.3}{1+4.8(1.2)^{-t}}$
Limiting value (level-off value) is $N=6.3$
