Answer
$P(x)\approx 24.70(1.054)^{x}$
Work Step by Step
For small x,
$f(x)=\displaystyle \frac{N}{1+Ab^{-x}}\approx(\frac{N}{1+A})b^{x}$
the logistic function grows approximately exponentially with base b.
From the given model,
$N=86.2,\ A=2.49, b=1.054$
so for small x,
$P(x)\displaystyle \approx\frac{86.2}{3.49}(1.054)^{x}\approx 24.70(1.054)^{x}$
