Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.4 - Logistic Functions and Models - Exercises - Page 669: 27

Answer

$f(t)=\displaystyle \frac{10,000}{1+9(1.25)^{-t}}$ $f(7)\approx 3463$ cases

Work Step by Step

Logistic Model form: $\displaystyle \quad f(t)=\frac{N}{1+Ab^{-t}}$ $N$ is the limiting value, the total population. $N=10,000$ Now (t=0 days), we are given $f(0)=1000 \quad \Rightarrow \quad \left\{\begin{array}{ll} 1000 & =\dfrac{10000}{1+Ab^{-0}}\\ 1+Ab^{-0} & =\dfrac{10000}{1000}\\ A & =10-1\\ A & =9 \end{array}\right.$ The rate of increase was $ 25\%$ per day, which corresponds to a factor $b=100\%+25\%=1.25$ $f(t)=\displaystyle \frac{10,000}{1+9(1.25)^{-t}}$ A week from now, $t=7$ days, we have: $f(7)\approx 3463$ cases
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