Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 14 - Section 14.1 - Integration by Parts - Exercises - Page 1021: 1

Answer

$\int2xe^xdx=2xe^x-2e^x+C$

Work Step by Step

We integrate as follows: $u=2x$ $D(u)=2$ $v=e^x$ $I(v)=e^x$ $\int u·v~dx=u·I(v)-\int D(u)I(v)dx$ $\int2xe^xdx=2xe^x-\int 2e^xdx=2xe^x-2e^x+C$
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