Answer
$\int2xe^xdx=2xe^x-2e^x+C$
Work Step by Step
We integrate as follows:
$u=2x$
$D(u)=2$
$v=e^x$
$I(v)=e^x$
$\int u·v~dx=u·I(v)-\int D(u)I(v)dx$
$\int2xe^xdx=2xe^x-\int 2e^xdx=2xe^x-2e^x+C$
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