Answer
diverges to $-\infty$
Work Step by Step
when $t\rightarrow+\infty,$
$3t\rightarrow+\infty\ \ \ ,$ (determinate form $ k(\pm\infty)=\pm\infty$)
$ e^{3t}\rightarrow+\infty\ \ \ $ (determinate form $k^{+\infty}=+\infty,$ k$=e>1$)
$2e^{3t}\rightarrow+\infty\ \ \ $ (determinate form $ k(\pm\infty)=\pm\infty$)
$4.1-2e^{3t}\rightarrow-\infty\ \ \ $ (determinate form $ k\pm\infty=\pm\infty$)
$\displaystyle \lim_{t\rightarrow+\infty}f(\mathrm{t}) $diverges to $-\infty$
